Class 5 HCF
HCF Practice Problems
Highest Common Factor (HCF) using Prime Factorization and Long Division Methods
Find the Highest Common Factor (HCF) of the following numbers using the specified method.
| Problem | Method | Solution Steps | Answer |
|---|---|---|---|
| 1a. 50 and 75 | Prime Factorization |
50 = 2 × 5² 75 = 3 × 5² HCF = 5² = 25 |
25 |
| 1b. 245 and 375 | Prime Factorization |
245 = 5 × 7² 375 = 3 × 5³ HCF = 5 |
5 |
| 1c. 225 and 625 | Prime Factorization |
225 = 3² × 5² 625 = 5⁴ HCF = 5² = 25 |
25 |
| 1d. 18, 54, 72 | Prime Factorization |
18 = 2 × 3² 54 = 2 × 3³ 72 = 2³ × 3² HCF = 2 × 3² = 18 |
18 |
| 1e. 65, 90, 105 | Prime Factorization |
65 = 5 × 13 90 = 2 × 3² × 5 105 = 3 × 5 × 7 HCF = 5 |
5 |
| 1f. 72, 99, 108 | Prime Factorization |
72 = 2³ × 3² 99 = 3² × 11 108 = 2² × 3³ HCF = 3² = 9 |
9 |
| 1g. 96, 144, 168 | Prime Factorization |
96 = 2⁵ × 3 144 = 2⁴ × 3² 168 = 2³ × 3 × 7 HCF = 2³ × 3 = 24 |
24 |
| 1h. 80, 110, 210 | Prime Factorization |
80 = 2⁴ × 5 110 = 2 × 5 × 11 210 = 2 × 3 × 5 × 7 HCF = 2 × 5 = 10 |
10 |
| 1i. 675, 275, 325 | Prime Factorization |
675 = 3³ × 5² 275 = 5² × 11 325 = 5² × 13 HCF = 5² = 25 |
25 |
| 1j. 117, 65 and 78 | Prime Factorization |
117 = 3² × 13 65 = 5 × 13 78 = 2 × 3 × 13 HCF = 13 |
13 |
| 2a. 105, 252 | Long Division |
252 ÷ 105 = 2 rem 42 105 ÷ 42 = 2 rem 21 42 ÷ 21 = 2 rem 0 HCF = 21 |
21 |
| 2b. 540, 360 | Long Division |
540 ÷ 360 = 1 rem 180 360 ÷ 180 = 2 rem 0 HCF = 180 |
180 |
| 2c. 987, 462 | Long Division |
987 ÷ 462 = 2 rem 63 462 ÷ 63 = 7 rem 21 63 ÷ 21 = 3 rem 0 HCF = 21 |
21 |
| 2d. 924, 1320 | Long Division |
1320 ÷ 924 = 1 rem 396 924 ÷ 396 = 2 rem 132 396 ÷ 132 = 3 rem 0 HCF = 132 |
132 |
| 2e. 1440, 960 | Long Division |
1440 ÷ 960 = 1 rem 480 960 ÷ 480 = 2 rem 0 HCF = 480 |
480 |
| 2f. 1190, 1540 | Long Division |
1540 ÷ 1190 = 1 rem 350 1190 ÷ 350 = 3 rem 140 350 ÷ 140 = 2 rem 70 140 ÷ 70 = 2 rem 0 HCF = 70 |
70 |
| 2g. 1980, 1350 | Long Division |
1980 ÷ 1350 = 1 rem 630 1350 ÷ 630 = 2 rem 90 630 ÷ 90 = 7 rem 0 HCF = 90 |
90 |
| 2h. 252, 375, 420 | Long Division |
First find HCF of 252 and 375: 375 ÷ 252 = 1 rem 123 252 ÷ 123 = 2 rem 6 123 ÷ 6 = 20 rem 3 6 ÷ 3 = 2 rem 0 → HCF = 3 Now find HCF of 3 and 420: 420 ÷ 3 = 140 rem 0 HCF = 3 |
3 |
| 2i. 144, 252, 360 | Long Division |
First find HCF of 144 and 252: 252 ÷ 144 = 1 rem 108 144 ÷ 108 = 1 rem 36 108 ÷ 36 = 3 rem 0 → HCF = 36 Now find HCF of 36 and 360: 360 ÷ 36 = 10 rem 0 HCF = 36 |
36 |
| 2j. 2520, 3360, 4680 | Long Division |
First find HCF of 2520 and 3360: 3360 ÷ 2520 = 1 rem 840 2520 ÷ 840 = 3 rem 0 → HCF = 840 Now find HCF of 840 and 4680: 4680 ÷ 840 = 5 rem 480 840 ÷ 480 = 1 rem 360 480 ÷ 360 = 1 rem 120 360 ÷ 120 = 3 rem 0 HCF = 120 |
120 |
HCF Calculation Tips
- Prime Factorization Method: Find common prime factors with the smallest exponents
- Long Division Method: Divide larger number by smaller, then divide divisor by remainder, repeat until remainder is 0
- For three numbers, find HCF of two numbers first, then find HCF of that result with the third number
- HCF is always less than or equal to the smallest number
Practice these HCF problems to master the concepts!
Gyankatta Math Learning Resource • HCF Practice
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