{"id":162993,"date":"2026-03-26T17:54:00","date_gmt":"2026-03-26T17:54:00","guid":{"rendered":"https:\/\/news.gyankatta.org\/?p=162993"},"modified":"2026-02-26T18:07:19","modified_gmt":"2026-02-26T18:07:19","slug":"class-9-mathematics-question-paper","status":"publish","type":"post","link":"https:\/\/news.gyankatta.org\/?p=162993","title":{"rendered":"Class 9 \u2013 Mathematics Question Paper"},"content":{"rendered":"\n<p><\/p>\n\n\n\n<p>Time: 3 Hours Maximum Marks: 80<br><strong><\/strong><\/p>\n\n\n\n<p><strong>Section A \u2013 MCQs (1 \u00d7 20 = 20 Marks)<\/strong><\/p>\n\n\n\n<p>1. Rationalize: 1 \/ \u221a5<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) \u221a5<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) \u221a5 \/ 5<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) 5\u221a5<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) 1\/5<\/p>\n\n\n\n<p>2. (2\u00b3)\u00b2 =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) 2\u2075<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) 2\u2076<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) 4\u2076<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) 8\u00b2<\/p>\n\n\n\n<p>3. Degree of polynomial 5x\u00b3 + 2x\u00b2 \u2212 x + 7 is:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) 1<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) 2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) 3<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) 4<\/p>\n\n\n\n<p>4. If p(x) = x\u00b2 \u2212 4, then p(2) =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) 0<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) 2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) 4<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) \u22124<\/p>\n\n\n\n<p>5. If (x \u2212 3) is a factor of a polynomial, then remainder on division by (x \u2212 3) is:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) 1<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) 0<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) 3<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) \u22123<\/p>\n\n\n\n<p>6. (a + b)\u00b2 =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) a\u00b2 + b\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) a\u00b2 + 2ab + b\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) a\u00b2 \u2212 2ab + b\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) 2a\u00b2 + 2b\u00b2<\/p>\n\n\n\n<p>7. Two equal chords of a circle are:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) Parallel<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) Equal in length<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) Perpendicular<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) Diameter<\/p>\n\n\n\n<p>8. Radius of a circle is 7 cm. Diameter is:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) 7 cm<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) 14 cm<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) 21 cm<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) 49 cm<\/p>\n\n\n\n<p>9. Heron\u2019s formula is used to find:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;a) Perimeter<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;b) Area of triangle<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;c) Volume<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;d) Circumference<\/p>\n\n\n\n<p>10. Curved surface area of a cone =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) \u03c0r\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) 2\u03c0rh<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) \u03c0rl<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) 4\u03c0r\u00b2<\/p>\n\n\n\n<p>11. Volume of sphere =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) 4\/3 \u03c0r\u00b3<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) \u03c0r\u00b2h<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) 2\u03c0r\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) \u03c0r\u00b3<\/p>\n\n\n\n<p>12. If frequency of a class is zero, it means:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) No observation<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) Negative observation<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) Infinite observation<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) One observation<\/p>\n\n\n\n<p>13. Histogram is used for:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) Ungrouped data<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) Grouped continuous data<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) Pie chart<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) Probability<\/p>\n\n\n\n<p>14. If mean = 10 and number of observations = 5, total sum =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) 2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) 15<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) 50<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) 5<\/p>\n\n\n\n<p>15. (x\u00b3 \u2212 1) is divisible by:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) x \u2212 1<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) x + 1<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) x \u2212 3<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) x + 3<\/p>\n\n\n\n<p>16. \u221a18 can be simplified as:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) 3\u221a2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) 2\u221a3<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) 9\u221a2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) 6\u221a3<\/p>\n\n\n\n<p>17. If radius doubles, volume of sphere becomes:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) Double<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) 4 times<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) 6 times<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) 8 times<\/p>\n\n\n\n<p>18. Sum of frequencies in a distribution is called:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) Mean<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) Total frequency<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) Class interval<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) Mode<\/p>\n\n\n\n<p>19. In a circle, perpendicular from centre to chord:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) Bisects the chord<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) Doubles the chord<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) Is tangent<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) Is radius<\/p>\n\n\n\n<p>20. (a \u2212 b)(a + b) =<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;a) a\u00b2 + b\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;b) a\u00b2 \u2212 b\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;c) a\u00b2 \u2212 2ab + b\u00b2<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;d) a\u00b2 + 2ab + b\u00b2<\/p>\n\n\n\n<p><strong>Section B \u2013 Very Short Answer (2 \u00d7 5 = 10 Marks)<\/strong><\/p>\n\n\n\n<p>1. Rationalize: 5 \/ \u221a3<\/p>\n\n\n\n<p>2. Find degree of polynomial 7x\u2074 \u2212 3x + 9.<\/p>\n\n\n\n<p>3. If p(x) = x\u00b3 \u2212 2x\u00b2 + 1, find p(1).<\/p>\n\n\n\n<p>4. Find curved surface area of cone of radius 7 cm and slant height 10 cm.<\/p>\n\n\n\n<p>5. Find mean of 5, 7, 9.<\/p>\n\n\n\n<p><strong>Section C \u2013 Short Answer Questions (3 \u00d7 6 = 18 Marks)<\/strong><\/p>\n\n\n\n<p>1. Factorize: x\u00b3 \u2212 27.<\/p>\n\n\n\n<p>2. Using Remainder Theorem, find remainder when x\u00b3 \u2212 3x\u00b2 + 2 is divided by (x \u2212 2).<\/p>\n\n\n\n<p>3. Prove: Equal chords of a circle subtend equal angles at the centre.<\/p>\n\n\n\n<p>4. Find area of triangle with sides 7 cm, 8 cm, 9 cm using Heron\u2019s formula.<\/p>\n\n\n\n<p>5. Find volume of sphere of radius 7 cm.<\/p>\n\n\n\n<p>6. Construct a frequency polygon from given grouped data.<\/p>\n\n\n\n<p><strong>Section D \u2013 Long Answer Questions (5 \u00d7 4 = 20 Marks)<\/strong><\/p>\n\n\n\n<p>1. Simplify using identities:<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;(2x + 5)\u00b2 \u2212 (2x \u2212 5)\u00b2<\/p>\n\n\n\n<p>2. Prove that perpendicular from centre to chord bisects the chord.<\/p>\n\n\n\n<p>3. Find total surface area and volume of a cone of radius 7 cm and height 24 cm.<\/p>\n\n\n\n<p>4. The following data shows marks of students:<\/p>\n\n\n\n<p>Class Interval:<\/p>\n\n\n\n<p>0\u201310, 10\u201320, 20\u201330, 30\u201340, 40\u201350<\/p>\n\n\n\n<p>Frequency:<\/p>\n\n\n\n<p>3, 5, 9, 7, 6<\/p>\n\n\n\n<p>(a) Construct histogram<\/p>\n\n\n\n<p>(b) Find total frequency<\/p>\n\n\n\n<p><strong>Section E \u2013 Case Study Based Questions (4 \u00d7 3 = 12 Marks)<\/strong><\/p>\n\n\n\n<p><strong>Case Study 1:<\/strong><\/p>\n\n\n\n<p>A tent is in the shape of a cone placed on a circular base. Radius = 7 m, height = 24 m.<\/p>\n\n\n\n<p>(i) Find slant height.<\/p>\n\n\n\n<p>(ii) Find curved surface area.<\/p>\n\n\n\n<p>(iii) Find volume of tent.<\/p>\n\n\n\n<p><strong>Case Study 2:<\/strong><\/p>\n\n\n\n<p>A survey of 40 students\u2019 marks is grouped into class intervals.<\/p>\n\n\n\n<p>(i) Why is histogram suitable here?<\/p>\n\n\n\n<p>(ii) What is total frequency?<\/p>\n\n\n\n<p>(iii) How is frequency polygon drawn?<\/p>\n\n\n\n<p><strong>Case Study 3:<\/strong><\/p>\n\n\n\n<p>A triangle has sides 13 cm, 14 cm, 15 cm.<\/p>\n\n\n\n<p>(i) Find semi-perimeter.<\/p>\n\n\n\n<p>(ii) Find area using Heron\u2019s formula.<\/p>\n\n\n\n<p>(iii) Verify area using identity method if possible.<br><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Time: 3 Hours Maximum Marks: 80 Section A \u2013 MCQs (1 \u00d7 20 = 20 Marks) 1. Rationalize: 1 \/ \u221a5 &nbsp;&nbsp;&nbsp;a) \u221a5 &nbsp;&nbsp;&nbsp;b) \u221a5 \/ 5 &nbsp;&nbsp;&nbsp;c) 5\u221a5 &nbsp;&nbsp;&nbsp;d) 1\/5 2. (2\u00b3)\u00b2 = &nbsp;&nbsp;&nbsp;a) 2\u2075 &nbsp;&nbsp;&nbsp;b) 2\u2076 &nbsp;&nbsp;&nbsp;c) 4\u2076&#8230;<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-162993","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Class 9 \u2013 Mathematics Question Paper - Gyankatta<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/news.gyankatta.org\/?p=162993\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Class 9 \u2013 Mathematics Question Paper - Gyankatta\" \/>\n<meta property=\"og:description\" content=\"Time: 3 Hours Maximum Marks: 80 Section A \u2013 MCQs (1 \u00d7 20 = 20 Marks) 1. 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Rationalize: 1 \/ \u221a5 &nbsp;&nbsp;&nbsp;a) \u221a5 &nbsp;&nbsp;&nbsp;b) \u221a5 \/ 5 &nbsp;&nbsp;&nbsp;c) 5\u221a5 &nbsp;&nbsp;&nbsp;d) 1\/5 2. 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